sum of the two number is 42 . 4 times the smaller number is equal to 3 times the larger number find the number
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let the two numbers be x and y
in which x is smaller
a/q from 1st part-
x+y=42 ------(I)
a/q from 2nd part-
4x=3y
4x-3y=0 -----(ii)
multiplying eq I by 3 and adding eq I and ii
3x+3y=126
4x-3y=0
_________
7x=126
x= 126/7
x=18
putting x=18 in eq I
18+y=42
y=42-18
y=24
so, x=18
y=24
Hope it is useful
in which x is smaller
a/q from 1st part-
x+y=42 ------(I)
a/q from 2nd part-
4x=3y
4x-3y=0 -----(ii)
multiplying eq I by 3 and adding eq I and ii
3x+3y=126
4x-3y=0
_________
7x=126
x= 126/7
x=18
putting x=18 in eq I
18+y=42
y=42-18
y=24
so, x=18
y=24
Hope it is useful
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