Sum of the two numbers is 19 and the difference between the squares is 95 determine the product of two numbers
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let one no. be x
other be y
ATQ
x+y=19 ....1
(let x>y)
therefore,x2-y2=95
(x+y)(x-y)=95
19(x-y)=95
(x-y)=5 .....2
by eliminating the two equations, 1 and 2
we will get y=7 and x=12
then product of the no. is x×y=12×7=84
other be y
ATQ
x+y=19 ....1
(let x>y)
therefore,x2-y2=95
(x+y)(x-y)=95
19(x-y)=95
(x-y)=5 .....2
by eliminating the two equations, 1 and 2
we will get y=7 and x=12
then product of the no. is x×y=12×7=84
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