Question

Sum of the two numbers is 39 and product is 108

Answer 1

Answer:

Step-by-step explanation:

Let the 2 no.s be x and y

given:-

x+y=39................1

xy=108................2

therefore,

xy=108

x=108/y...............substitute in 1

x+y=39

(108/y) + y = 39

(108+$y^{2}$)/y = 39

108 + $y^{2}$ = 39y

$y^{2}$ - 39y + 108 = 0

$y^{2}$ - (36y+3y) + 108 = 0

$y^{2}$ - 3y - 36y + 108 = 0

y ( y - 3 ) - 36 ( y - 3 ) = 0

( y - 3 ) ( y - 36 ) = 0

therefore,

y-3=0                or          y-36=0

y=3                                 y=36

let y=3               or         y=36

thus x=36                      x=3

therfore the two numbers are 36 and 3