Math, asked by Smilypriya, 11 months ago

sum of the zeroes of the polynomial 6x^2-7​

Answers

Answered by ravinakumari1967
0

Answer:

6x^2-7=0

Sum of zeroes=-b/a

=0/6=0

Answered by wwwguwahatiyuvi11
0

p(x)=6x²-7

For the zeroes,

6x²-7=0

6x²=7

x²=7/6

x=±√7/6

p(x)=6x²+0x-7

Now,

Sum of zeroes=+√7/6+(-√7/6)=-b/a

=0=0

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