sum of the zeroes of the polynomial 6x^2-7
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Answer:
6x^2-7=0
Sum of zeroes=-b/a
=0/6=0
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p(x)=6x²-7
For the zeroes,
6x²-7=0
6x²=7
x²=7/6
x=±√7/6
p(x)=6x²+0x-7
Now,
Sum of zeroes=+√7/6+(-√7/6)=-b/a
=0=0
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