Question

Sum of thousand is in the form of denominator of rupees 20 and 10 of the total number of notes 60, find the number of ₹20notes ​

Answer 1

$\Large{\underline{\underline{\bf{AnSweR:-}}}}$

$\large\sf \bf{ \underline{Let:- }}$

$❥ \ \mathtt{No. \: of \: ₹ 10 \: notes \: as \: 'x' }$

$\ ❥ \ \mathtt{No. \: of \: ₹ 60 \: notes \: as \: 'y' }$

$\Large{\underline{\underline{\bf{GiVen:-}}}}$

$\ \ ❥ \ {Total \: <strong>sum</strong><strong> </strong><strong>↠</strong> ₹1000}$

$❥ \mathtt{Number \: of \: notes ↠ 60}$

$\Large{\underline{\underline{\bf{SoLuTion:-}}}}$

────⊱◈◈◈⊰────

$❥ \ \bf{x+y=60}$

$\ ❥ \ \bf{x=60-y \: ━━ \: Eq. 1}$

$\ ❥ \ \bf{10x+50y=1000 \: ━━ \: Eq.2}$

$\mathtt {Substituting \: \: Eq.1 \: in \: Eq.2 :- }$

$\ ❥ \ \bf{10(60-y) + 50y =1000</p><p>}$

$\ ❥ \ \bf{</p><p>600-10y+50y=1000}$

$\ ❥ \ \bf{40y=1000-600}$

$\ ❥ \ \bf{40y=400}$

$\ ❥ \ \bf{y=10}$

$\mathtt{So \: now \: for \: x:- }$

$\ ❥ \ \bf{x=60-y}$

$\ ❥ \ \bf{x = 60 - 10}$

$\ ❥ \ \bf{x=50}$

ྉ No. of 10 Rupees notes:- 50

ྉ No. of 60 Rupees notes :- 10

❧ Total :- 60 notes

────⊱◈◈◈⊰────

Answer 2

Answer:

Mark me as Brainliest please....