Question

sum of three concecutive multiples of 8 is 888 .find the multiples

Answer 1

let the consecutive multiples of 8 be
$8k \: \: 8(k + 1) \: \: and \: 8(k + 2) \\ sum = 888 \\ 8k + 8(k + 1) + 8(k + 2) = 888 \\ k + k + 1 + k + 2 = 111 \\ 3k = 108 \\ k = 36 \\ put \: value \: of \: k \: there$

Answer 2

Thats it
Here is ur ans
Hope you know it....