sum of three consecutive even numbers is 36. find the numbers
Answers
Answer:
Let,
First number is 2x
Second number is 2x+2
Third number is 2x+4
(Because these are consecutive)
According to given condition,
2x+2x+2+2x+4 = 36
=> 6x+6= 36
=> 6x+6–6=36–6
=> 6x = 30
=> 6x/6 = 30/6
=> x = 5
So, first number is =2*5=10
Second number is =2*5+2=12
Third number is =2*5+4=14
Now,
10+12+14=36
=>36=36.
Answer: 10,12,14.
Explanation:
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Answer:
Three consecutive integers whose sum is 36 are 10, 12, and 14.
Explanation:
Let 2n = the first even number, where n is an integer.
Let 2n + 2 = the second even number, and ...
Let 2n + 4 = the third even number.
With the above three equalities in mind, the statement that, "The sum of three consecutive even numbers is 36" can be translated mathematically into the following equation to be solved for n:
2n + (2n + 2) + (2n + 4) = 36
2n + 2n + 2 + 2n + 4 = 36
Collecting like-terms on the left, we have:
6n + 6 = 36
6n + 6 - 6 = 36 - 6
6n + 0 = 30
6n = 30
(6n)/6 = 30/6
(6/6)n = 5
(1)n = 5
n = 5
Therefore, ...
2n = 2(5) = 10
2n + 2 = 10 + 2 = 12
2n + 4 = 10 + 4 = 14
CHECK:
2n + (2n + 2) + (2n + 4) = 36
2(5) + (2(5) + 2) + (2(5) + 4) = 36
10 + 12 + 14 = 36
36 = 36
Therefore, the three consecutive even numbers are: 10, 12, and 14.
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