Question

sum of three consecutive integers is 336 find them

Answer 1

Here we will use algebra to find three consecutive integers whose sum is 336.

We assign X to the first integer. Since they are consecutive, it means that the 2nd number will be X+1 and the third number will be X+2 and they should all add up to 336. Therefore, you can write the equation as follows:

X + X + 1 + X + 2 = 336

To solve for X, you first add the integers together and the X variables together. Then you subtract 3 from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 336
3X + 3 = 336

3X + 3 - 3 = 336 - 3
3X = 333

3X/3 = 333/3
X = 111

Which means that the first number is 111, the second number is 111+1 and third number is 111+2. Therefore, three consecutive integers that add up to 336 are:

111
112
113.

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Answer 2

let a (a+1)(a+2)be the integers
a+a+1+a+2=336
3a=336-3=333
a=333/3=111
numbers are 111&112&113