Question

sum of three consecutive integers is 63 find the integers

Answer 1

Let the first integer be a

Second integer = a + 1

Third integer = a + 2

According to question,

a + a + 1 + a + 2 = 63

=> 3a + 3 = 63

=> 3a = 60

=> a = 20


First integer = 20

Second integer = 21

Third integer = 22

Answer 2

Concept:

An integer is generally defined as a number which can be written without a fractional component that is it is a whole number. For example, 2, - 4, 0, and −2048.

Given:

We are given that the sum of three consecutive integers is 63.

Find:

We need to find these integers.

Solution:

Let the middle integer be x.

So, the first integer will be:

x - 1

And the third integer will be:

x + 1

Now ATQ:

(x - 1) + (x + 1) + x = 63

3 x = 63

x = 21

So, the numbers will be:

x - 1 = 21 - 1 = 20

x = 21

x + 1 = 21 + 1 = 22

Therefore, the integers are 20, 21 and 22.

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