sum of three consecutive multiple of 7 is 70 find the multiples
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soln: let the three consecutive multiples of 7 be 7x, 7x+7, 7x+14
A/q,
7x+7x+7+7x+14=70
21x+21=70
21x=70-21
21x= 49
x= 49/21
x= 2.333 Ans.
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