Question

Sum of three consecutive multiples of 9 is 243.Find numbers.

Answer 1

Let the multiples of 9 be x, x+9, x+18.

A/q,

➡ x + x+ 9 + x+ 18 = 243

➡ 3x + 27 = 243

➡ 3x = 216

➡ x = 216/3

➡ x = 72

so, required multiples of 9 =

➡ x = 72

➡ x + 9 = 72 + 9 = 81

➡ x + 18 = 72 + 18 = 90.

Hope it will help you !!

Answer 2

a+a+9+a+18=243
3a+27=243
3a=216
a=72

The three numbers are 72,81 and 90