Question

sum of three consecutive odd number is 987 find them

Answer 1

let the numbers be a, a+2, a+4
given,
a+(a+2)+(a+4)=987
a+a+2+a+4=987
3a+6=987
3(a+2)=987
a+2=987/3
a+2=329
a=329-2
a=327
so,
the numbers are 327, 329 & 331

Answer 2

let the numbers be x ,x+2,x+4
therefore,
x+(x+2)+(x+4) =987
3x+6 =987
3x =987-6
3x=981
x=981/3
x=327
x+2=327+2 =329
x+4 =327+4 =331