Sum of three consecutive positive integer such that the sum of the first integer and the product of the other two is 92
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let the first number be x so the next two numbers are x+1 and x+2
so it is given that
x + (x+1)*(x+2) = 92
x + x^2 + 2x + x + 2 = 92
x^2 + 4x - 90 = 0
now
x = [-b +- √(b^2 -4ac)]/2a
x = [-4 +- √(16 + 360)]/2
x = [-4 +- √(376)]/2
x = [-4 +- (19.4)]/2
srry no possible integer as the value coming in decimal
:-(
so it is given that
x + (x+1)*(x+2) = 92
x + x^2 + 2x + x + 2 = 92
x^2 + 4x - 90 = 0
now
x = [-b +- √(b^2 -4ac)]/2a
x = [-4 +- √(16 + 360)]/2
x = [-4 +- √(376)]/2
x = [-4 +- (19.4)]/2
srry no possible integer as the value coming in decimal
:-(
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