Question

sum of three consecutive terms of arithmetic progression is 42 and their product is 2520.find the terms of arthmetic progression​

Answer 1

Answer:

the answer is Right........

Answer 2

The terms of arthmetic progression are 10, 14 and 18.

Step-by-step explanation:

Let the three consecutive terms of arithmetic progression are a-d, a and a+d.

Given:

• Sum of three consecutive terms of arithmetic progression is 42 and their product is 2520.

$\rightarrow \: a - d + a + a + d = 42 \\ \rightarrow \: 3a = 42 \\ \rightarrow \: a = 14 \\ \rightarrow \: (a - d ) a ( a + d) = 2520 \\ \rightarrow \:( {a}^{2} - {d}^{2} )a = 2520 \\ \rightarrow \:( {14}^{2} - {d}^{2} )14 = 2520 \\ \rightarrow \:(196 - {d}^{2} ) = \frac{2520}{14} \\ \rightarrow \:(196 - {d}^{2} ) = 180 \\ \rightarrow \: {d}^{2} = 196 - 180 \\ \rightarrow \:{d}^{2} = 16 \\ \rightarrow \:d = 4$

So the terms are 10 ,14 and 18.