Question

sum of three digit numbers which are divisible by 9?​

Answer 1

ANSWER

Given that the three digit numbers which are divisible by 9 are

108,117,126,...999

Here a=108,d=117−108=9

∴n=

d

l−a

+1=

9

999−108

+1=

9

899

+1=99+1=100

∴S

100

=

2

100

[108+999]=50×1107=55,350

Answer 2

Answer:

sum of three digit numbers which are divisible by 9 is 55350