Question

Sum of three numbers in ap is 21 and the product of their extremes is 45. find the numbers

Answer 1

solve the last equation and get value of a then put this value in any equation and get value of c

Answer 2

Answer:

The three numbers are either 5,7,9 or 9,7,5.

Step-by-step explanation:

Let the three numbers be a-d, a, a+d.

It is given that the sum of these number is 21.

$a-d+a+a+d=21$

$3a=21$

$a=7$

The value of a is 7.

The product of their extremes is 45.

$(a-d)(a+d)=45$

$a^2-d^2=45$

$7^2-d^2=45$

$49-45=d^2$

$4=d^2$

$d=\pm 2$

The value of d is either 2 or -2.

Therefore the three numbers are either 5,7,9 or 9,7,5.