Question

The contents of urns i,ii and iii are as follows: 1 white,2 black and 3 red balls, 2 white, 1 black and 1 red balls, and 4 white, 5 black and 3 red balls. one urn is chosen at random and two balls drawn from it. they happen to be white and red.what is the probability that they come from urns i, ii or iii

Answer 1

\(E_1=1 \;Bag\; is\; chosen\)\(E_2=2 \;Bag\; is\; chosen\)\(A\;choising\;a\;black\;ball\)\(P(A)=P(E_1)P(A/E_1)+P(E_2)P(A/E_2)\)\(bag\; 1\; is\; chosen\; if \;1 \;or\; 3\; appear \;in \;throw\; of\; die\)\(P(E_1)=\Large\frac{2}{6}=\frac{1}{3}\)\(bag\; 2\; is\; chosen\; otherwise\)\(P(E_1)=1-\Large\frac{1}{3}=\frac{2}{3}\)