sum of triangle pls solve
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In ΔEHF and ΔGHF
EF=GF (given)
HF=HF (common)
EH=GH ( Given, that H is the midpoint of GE)
ΔEHF≅ΔGHF (By SSS≅)
∠EFH= ∠HFG (By CPCT, full form: Corresponding Parts of Congruent Triangle)---------(1)
From (1),
HF is the angle bisector of ∠EFG because, ∠EFH= ∠HFG.
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