Question

sum of two consecutive even numbers is 46. Find the smaller even number.

Answer 1

Answer:

let first number be x

Let the second number be x + 2

According to condition:

x + ( x+2) = 46

x +x +2=46

2x + 2 = 46

x = (46 - 2)/ 2

x = 22

So, the first number = x = 22

Second number = x+2 = 24

Hope this helps !

Step-by-step explanation:

Answer 2

Answer:

let two consecutive even numbers are x and x+2

$\: \: \: \: \: \: \: according \: to \: question \\ x + x + 2 = 46 \\ 2x + 2 = 46 \\ 2x = 44 \\ = > x = 22$

then small even number is 22