Sum of two consecutive multiples of 3 is 129 find the number
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LET THE FIRST NO. BE x
therefore 2nd no. x+ 3
THEREFORE x + x+3=129
=> 2x+ 3= 129
=> 2x= 129- 3
=> 2x= 126
=> x= 126/2
=> x = 63
therefore first no. = 63
2nd no. = 66
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