sum of two digit are 4 the diference obtainded by reversing the digit and by original number by 18 find number
Answers
Answered by
6
EXPLANATION.
Let the number at tens place be = x
Let the number at unit place be = y
original number = 10x + y
reversing number = 10y + x
To find the number.
Case = 1.
Sum of two digit number = 4
=> x + y = 4 .......(1)
Case = 2.
The difference obtained by reversing the
digit and by original number = 18
=> ( 10y + x) - ( 10x + y) = 18
=> 10y + x - 10x - y = 18
=> 9y - 9x = 18
=> y - x = 2 .......(2)
From equation (1) and (2) we get,
=> 2y = 6
=> y = 3
put the value of y = 3 in equation (1) we get,
=> x + 3 = 4
=> x = 1
Therefore,
original number = 10x + y = 10(1) + 3 = 13
Answered by
0
Step-by-step explanation:
hey mate here is your answer:
let the unit digit be :y
tens digit: 10x
given,
case 1,
10x+y=4
case 2,
(10y+x)-(10x+y)=18
10y+x-10x-y=18
9y-9x=18
9(y-x)=18
y-x=2
y+x=4
y-x=2
y=6
x=4
please mark as a brainliest
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