Question

sum of two digit are 4 the diference obtainded by reversing the digit and by original number by 18 find number​

Answer 1

EXPLANATION.

Let the number at tens place be = x

Let the number at unit place be = y

original number = 10x + y

reversing number = 10y + x

To find the number.

Case = 1.

Sum of two digit number = 4

=> x + y = 4 .......(1)

Case = 2.

The difference obtained by reversing the

digit and by original number = 18

=> ( 10y + x) - ( 10x + y) = 18

=> 10y + x - 10x - y = 18

=> 9y - 9x = 18

=> y - x = 2 .......(2)

From equation (1) and (2) we get,

=> 2y = 6

=> y = 3

put the value of y = 3 in equation (1) we get,

=> x + 3 = 4

=> x = 1

Therefore,

original number = 10x + y = 10(1) + 3 = 13

Answer 2

Step-by-step explanation:

hey mate here is your answer:

let the unit digit be :y

tens digit: 10x

given,

case 1,

10x+y=4

case 2,

(10y+x)-(10x+y)=18

10y+x-10x-y=18

9y-9x=18

9(y-x)=18

y-x=2

y+x=4

y-x=2

y=6

x=4

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