sum of two digit number is 45 the greater number be 8 more than the smaller number (Take smaller number to be x
Answers
Step-by-step explanation:
Let us say that the smaller number is
x
. Now, since the larger number is
8
more than the smaller number, it is
x
+
8
.
From the question, we know that their sum is
40
. We add the smaller number
x
to the larger number
x
+
8
to get
x
+
x
+
8
=
2
x
+
8
. This value is equal to
40
.
Therefore,
2
x
+
8
=
40
. In order to solve this equation, we have to remember that we can do anything to one side of the equation provided that we do the exact same thing to the other side.
Suppose that we subtract
8
from both sides:
2
x
+
8
−
8
=
40
−
8
. Simplifying, we get
2
x
=
32
.
Now, suppose we divide both sides by
2
:
2
x
÷
2
=
32
÷
2
. Simplifying, we get
x
=
16
.
We have our smaller number. Looking back, we said that the larger number is
8
more than the smaller number. Eight more than
16
is
24
.
Our smaller number is
16
, and our larger number is
24
. They do add up to
40
(since
16
+
24
=
40
).
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