Sum of two like fraction is 8/9 and their difference is 2/9
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6
According to the question,
Let the required fractions are x and y,
Given, sum of the required fractions = 8 / 9
∴ x + y = 8 / 9 ...( i )
Also given, difference of the required fractions = 2 / 9
∴ x - y = 2 / 9 ...( ii )
Now, adding ( i ) and ( ii ),
x + y = 8 / 9
x - y = 2 / 9_
2x = 10 / 9
⇒ x = 10 / 18
⇒ x = 5 / 9
Substituting the value of x in ( i ),
⇒ x + y = 8 / 9
⇒ 5 / 9 + y = 8 / 9
⇒ y = 8 / 9 - 5 / 9
⇒ y = ( 8 - 5 ) / 9
⇒ y = 3 / 9
Therefore, required fractions are 5 / 9 and 3 / 9 .
Answered by
0
Answer:
ans 5/9 and 3/9
Step-by-step explanation:
the only difference is 2/9
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