Question

Sum of two number is 50 and their
difference is 10 then the numbers are​

Answer 1

Answer:

Let the two numbers be x, y.

x+y = 50 [Eq 1]

x-y = 10 [Eq 2]

x = 50-y [From Eq - 1]

Substitute this value in Eq 2

x-y = 10

50-y -y = 10 [Add two negative numbers and assign a - sign]

50–2y = 10 [As numbers are transposed from one to another side their sign changes]

50 -10 = 2y

40 = 2y

Dividing by 2 both sides

40/2 = 2y/2

20 = y

x = 50-y

x = 50–20 = 30

x = 30, y = 20 :Final Answer

Step-by-step explanation:

hope it will help you

Answer 2

Answer:

let, two now be x and y

x + y = 50............(1)

x - y = 10...........(2)

from ,

substitution method

we can written eq 2 as

x = 10+y.........(3)

on putting in eq 1

10 + y + y = 50

10 + 2y = 50

2y = 50 - 10

2y = 40

y = 40/2

y = 20

on putting value of y in eq 3

x = 10 + 20

x = 30