sum of two number is 50.If the arger number is divided by the smaller number we get 4.Find the numbers
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2
Answer:
required numbers are 10 and 40
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0
Solution
Given :-
- Sum of two numbers = 50
- If the arger number is divided by the smaller number we get 4
Find :-
- These two number.
Explanation
Let,
- First Number be = x
- second number be = y
According to question .
( Sum of two number is 50)
==> x + y = 50_____________(1)
Again,
(If the arger number is divided by the smaller number we get 4)
==> x/y = 4
==> x = 4y
==> x - 4y = 0______________(2)
Subtract equ(1) & equ(2)
==> y + 4y = 50
==> 5y = 50
==> y = 50/5
==> y = 10
keep value of y in equ(1)
==> x + 10 = 50
==> x = 50 - 10
==> x = 40
Hence
- First Number be = 40
- Second Number be = 10
________________________
Answer Verification
According to question,
(If the arger number is divided by the smaller number we get 4)
==> x/y = 4
keep value of x & y
==> 40/10 = 4
==> 4 = 4
L.H.S. = R.H.S.
That's Proved.
___________________
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