Question

Sum of two number is 72.If one exceeds the other by 12, find the numbers. please give me an explanation answer and step by step answer for understanding me​

Answer 1

$\huge \bf \underline \bold \pink{answer}$

Let the number be x.

∴ Other number = x +12

According to question,

x + x + 12 = 72

⇒ 2x + 12 = 72 ⇒ 2x = 72 – 12 = 60

⇒ x = 60/2 = 30

∴ x + 12 = 30 + 12 = 42

Hence, the numbers are 30 and 42

Hope it's help uh...!!!

Answer 2

Answer:

$\it \underline \purple{solution}$

GIVEN

sum of the numbers = 72

one exceeds the other by 12

TO FIND

the numbers

ANSWER

let the first number be x

let the second number be (x - 12)

sum = 72 [given]

A/Q, we have :-

x + (x - 12) = 72

x + x - 12 = 72

2x = 72 + 12 = 84

$x = \frac{84}{2} = 42$

»»——⍟——««»»——⍟——««»»——⍟——««»»——⍟——««

1st number = x = 42

second number = x - 12 = 42 - 12 = 30

»»——⍟——««»»——⍟——««»»——⍟——««»»——⍟——««

checking ✅

LHS

42 + (42 - 12)

42 + 42 - 12

= 72

RHS

= 72

$\rm \pink{hence \: verified}$