Question

sum of two number is 7678 if one number is 4613 then find out the second number


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Answer 1

Answer:

• sum of two number is 7678 if one number is 4613 then find out the second number

Step-by-step explanation:

\begin{gathered}$x = (y + z) = (x + y) + z \\ \\ x = (y + z) = \frac{3}{4} + ( \frac{5}{6} + \frac{ - 7}{8} ) \\ \\ = \frac{3}{4} + ( \frac{20 + ( - 21)}{24} ) \\ \\ = \frac{3}{4} + ( \frac{ - 1}{24} ) \\ \\ = \frac{3}{4} + \frac{ - 1}{24} \\ \\ = \frac{18 + ( - 1)}{24} \\ \\ = \frac{17}{24} \\ \\ (x + y ) + z = ( \frac{3}{4} + \frac{5}{6} ) + \frac{ - 7}{8} \\ \\ = ( \frac{9 + 10}{12} ) + \frac{ - 7}{8} \\ \\ = \frac{19}{12} + \frac{ - 7}{8} \\ \\ = \frac{38 + ( - 21)}{24} \\ \\ = \frac{38 - 21}{24} \\ \\ = \frac{17}{24} \\ \\ x + (y + z) = (x + y) + z \\ \\\end{gathered} </p><p>[tex]x=(y+z)=(x+y)+z</p><p>x=(y+z)= </p><p>4</p><p>3</p><p> </p><p> +( </p><p>6</p><p>5</p><p> </p><p> + </p><p>8</p><p>−7</p><p> </p><p> )</p><p>= </p><p>4</p><p>3</p><p> </p><p> +( </p><p>24</p><p>20+(−21)</p><p> </p><p> )</p><p>= </p><p>4</p><p>3</p><p> </p><p> +( </p><p>24</p><p>−1</p><p> </p><p> )</p><p>= </p><p>4</p><p>3</p><p> </p><p> + </p><p>24</p><p>−1</p><p> </p><p> </p><p>= </p><p>24</p><p>18+(−1)</p><p> </p><p> </p><p>= </p><p>24</p><p>17</p><p> </p><p> </p><p>(x+y)+z=( </p><p>4</p><p>3</p><p> </p><p> + </p><p>6</p><p>5</p><p> </p><p> )+ </p><p>8</p><p>−7</p><p> </p><p> </p><p>=( </p><p>12</p><p>9+10</p><p> </p><p> )+ </p><p>8</p><p>−7</p><p> </p><p> </p><p>= </p><p>12</p><p>19</p><p> </p><p> + </p><p>8</p><p>−7</p><p> </p><p> </p><p>= </p><p>24</p><p>38+(−21)</p><p> </p><p> </p><p>= </p><p>24</p><p>38−21</p><p> </p><p> </p><p>= </p><p>24</p><p>17</p><p> </p><p> </p><p>x+(y+z)=(x+y)+z</p><p> </p><p> </p><p></p><p>verified$

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Answer 2

Answer:

Sum of the numbers = 7678

One of the number = 4613

Other Number = (7678-4613)

= 3065

Step-by-step explanation: