Question

Sum of two number is P and their multiplication
is Q then their difference will be :-
​

Answer 1

Answer:

Let the numbers be x and y

A/Q;

x+y=p

x*y=q

(x-y)^2=(x+y)^2-4xy

          =p^2-4q

Therefore ;

x-y=Root under(p^2-4q)

So the answer is option A.  

Step-by-step explanation:

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Answer 2

Hence the correct option is 1.

Given:

The Sum of two numbers is P and their multiplication is Q.

To find:

Their difference.

Solution:

Let the numbers be x and y.

Given that sum of two numbers is P and their multiplication is Q.

So, we can write-

$x + y = p \\ xy = q$

Now we know that-

$({x + y)}^{2} = {(x - y)}^{2} + 4xy \\ {p}^{2} - 4q = {(x - y)}^{2} \\ x - y = \sqrt{ {p}^{2} - 4q}$

Thus, putting the value of x+y and xy we get the value of x-y is $√P^2-4Q$.

Hence the correct option is 1.

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