Question

sum of two numbers is 11 and one of them is 3 greater than the other find the numbers​

Answer 1

Answer:

let one number be X.

another number is 3 more than first one. Then, (x+3).

x+(x+3)=11

2x+3=11

2x=11-3

2x=8

x=8/2

x=4

x+3=4+3=7.

so, the two numbers are 4 and 7

Answer 2

Answer:

4 and 7 are the required two numbers .

Step-by-step explanation:

Explanation:

Given , sum of two numbers is 11 and

one of them is 3 greater than the other

So, let the two numbers be 'x' and 'y'

Step 1:

Therefore , sum of two numbers which is x and y is 11

x+y = 11 ...........(i)

And  one of them is greater than the other by 3 which is given in the question  .

Let x is greater than y by 3

∴ x = y+3 .........(ii)

Now put the value of x = y+3 in equation (i)

we get ,  x+ y = 11

⇒(y + 3) + y = 11                       (where x = y+3)

⇒2y +3 = 11

⇒2y = 8

⇒y = 4

Here , we get the value of y = 4 .

Step 2:

Now ,put the value of y = 4 in any one of the given equation

Let put the value of  y = 4 in equation (ii)

⇒x = y+ 3

⇒x = 4+3 = 7          (where y = 4)

Final answer :

Hence, the required two numbers are 7 and 4 .