Question

sum of two numbers is 130 and their difference is 6.find the no.​

Answer 1

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Let the number be x and y

Acc. to que...

Case 1

x+y = 130

x=130-y

Case 2

x-y=6

130-y-y=6

-2y=-124

y=62

x=130-62

x= 68

Answer 2

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$\large\mathcal\red{solution}$

let the numbers are X and y ...where..(X>y)

now... condition..1

=>X+y =130

=>X=130-y

now .. condition...2

=>X-y=6

=>130-y-y=6. [putting..X=130-y]

=>2y=124

=>y=124/2=62

therefore...X=62+6=68

the numbers are ....62 and 68

hope this helps you