Question

Sum of two numbers is 20 and the difference between thejr square is 100. Determine the product of the number

Answer 1

$<b>$Let one number be x

Let the second number be 20 - x

The difference between their square is 100 = x² - (20 - x)² = 100

A/q,

x² - (20 - x)² = 100

x² - (20² - 40x + x²) = 100

x² - 400 + 40x - x² = 100

40x - 400 = 100

40x = 500

x = $\frac{500}{40}$

x = 12.5

1st number => x => 12.5

2nd number => 20 - x => 20 - 12.5 => 7.5

$\therefore{}$ The numbers are 12.5 and 7.5

Answer 2

$<b><i>Solutions :-$

______________________
Let first number be x

And the second number = 20 - x

The difference between their square is 100
= x² - (20 - x)² = 100

A/q

=> x² - (20 - x)² = 100

=> x² - (20² - 40x + x²) = 100

=> x² - 400 + 40x - x² = 100

=> 40x - 400 = 100

=> 40x = 500

=> x = 500/40 = 12.5

So,

First number = x = 12.5

Second number = 20 - x = 20 - 12.5 = 7.5

Hence,

The numbers are 12.5 and 7.5
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