sum of two numbers is 20 and their product is 64 find the numbers
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Let the two numbers be x and y.
Given,
sum of two numbers is 20.
x + y = 20.
y = (20 - x) ----- (1)
Given,
product of two numbers = 64.
xy = 64 ------- (2)
Substitute (1) in (2),
x (20 - x) = 64
20x - x^2 = 64
-x^2 + 20x - 64 = 0
-1(x^2 - 20x + 64) = 0
x^2 - 20x + 64 = 0
x^2 - 16x - 4x + 64 = 0
x(x - 16) - 4(x - 16) = 0
(x - 16)(x - 4) = 0
x = 16 and x = 4.
Therefore,
the 2 numbers are 16 and 4.
From eq 1
x + y = 20
16 + 4 = 20.
20 = 20.
From (2)
xy = 64
16 × 4 = 64
HOPE THIS HELPS U. .
Given,
sum of two numbers is 20.
x + y = 20.
y = (20 - x) ----- (1)
Given,
product of two numbers = 64.
xy = 64 ------- (2)
Substitute (1) in (2),
x (20 - x) = 64
20x - x^2 = 64
-x^2 + 20x - 64 = 0
-1(x^2 - 20x + 64) = 0
x^2 - 20x + 64 = 0
x^2 - 16x - 4x + 64 = 0
x(x - 16) - 4(x - 16) = 0
(x - 16)(x - 4) = 0
x = 16 and x = 4.
Therefore,
the 2 numbers are 16 and 4.
From eq 1
x + y = 20
16 + 4 = 20.
20 = 20.
From (2)
xy = 64
16 × 4 = 64
HOPE THIS HELPS U. .
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