Question

Sum of two numbers is 29 and one number exceeds another by 5. Find the numbers
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Answer 1

Answer:

12 and 17

Step-by-step explanation:

Let the smaller number 'x', then the bigger number will be 'x+5".

Let the smaller number 'x', then the bigger number will be 'x+5".But it is given that sum of these two numbers is 29

Let the smaller number 'x', then the bigger number will be 'x+5".But it is given that sum of these two numbers is 29⇒ x+x+5=29

Let the smaller number 'x', then the bigger number will be 'x+5".But it is given that sum of these two numbers is 29⇒ x+x+5=29⇒ 2x+5=29

Let the smaller number 'x', then the bigger number will be 'x+5".But it is given that sum of these two numbers is 29⇒ x+x+5=29⇒ 2x+5=29∴ 2x=29−5

Let the smaller number 'x', then the bigger number will be 'x+5".But it is given that sum of these two numbers is 29⇒ x+x+5=29⇒ 2x+5=29∴ 2x=29−5∴ 2x=24

Let the smaller number 'x', then the bigger number will be 'x+5".But it is given that sum of these two numbers is 29⇒ x+x+5=29⇒ 2x+5=29∴ 2x=29−5∴ 2x=24x=

Let the smaller number 'x', then the bigger number will be 'x+5".But it is given that sum of these two numbers is 29⇒ x+x+5=29⇒ 2x+5=29∴ 2x=29−5∴ 2x=24x= 2

Let the smaller number 'x', then the bigger number will be 'x+5".But it is given that sum of these two numbers is 29⇒ x+x+5=29⇒ 2x+5=29∴ 2x=29−5∴ 2x=24x= 224

Let the smaller number 'x', then the bigger number will be 'x+5".But it is given that sum of these two numbers is 29⇒ x+x+5=29⇒ 2x+5=29∴ 2x=29−5∴ 2x=24x= 224

Let the smaller number 'x', then the bigger number will be 'x+5".But it is given that sum of these two numbers is 29⇒ x+x+5=29⇒ 2x+5=29∴ 2x=29−5∴ 2x=24x= 224 (Transposing '2' to RHS)

Let the smaller number 'x', then the bigger number will be 'x+5".But it is given that sum of these two numbers is 29⇒ x+x+5=29⇒ 2x+5=29∴ 2x=29−5∴ 2x=24x= 224 (Transposing '2' to RHS)x=12

Let the smaller number 'x', then the bigger number will be 'x+5".But it is given that sum of these two numbers is 29⇒ x+x+5=29⇒ 2x+5=29∴ 2x=29−5∴ 2x=24x= 224 (Transposing '2' to RHS)x=12Therefore smaller number =x=12 and

Let the smaller number 'x', then the bigger number will be 'x+5".But it is given that sum of these two numbers is 29⇒ x+x+5=29⇒ 2x+5=29∴ 2x=29−5∴ 2x=24x= 224 (Transposing '2' to RHS)x=12Therefore smaller number =x=12 andBigger number =x+5=12+5=17

Let the smaller number 'x', then the bigger number will be 'x+5".But it is given that sum of these two numbers is 29⇒ x+x+5=29⇒ 2x+5=29∴ 2x=29−5∴ 2x=24x= 224 (Transposing '2' to RHS)x=12Therefore smaller number =x=12 andBigger number =x+5=12+5=17Thus the required numbers are 12 and 17

Let the smaller number 'x', then the bigger number will be 'x+5".But it is given that sum of these two numbers is 29⇒ x+x+5=29⇒ 2x+5=29∴ 2x=29−5∴ 2x=24x= 224 (Transposing '2' to RHS)x=12Therefore smaller number =x=12 andBigger number =x+5=12+5=17Thus the required numbers are 12 and 17Hope it helps..

Let the smaller number 'x', then the bigger number will be 'x+5".But it is given that sum of these two numbers is 29⇒ x+x+5=29⇒ 2x+5=29∴ 2x=29−5∴ 2x=24x= 224 (Transposing '2' to RHS)x=12Therefore smaller number =x=12 andBigger number =x+5=12+5=17Thus the required numbers are 12 and 17Hope it helps..Pls mark as brainliest..

Answer 2

Answer:

12 and 17

Step-by-step explanation:

Let X and Y be the two numbers.

By question,

X + Y = 29

X = Y + 5

=>X + Y = 29

=>Y + 5 + Y = 29 (Since X = Y + 5)

=>2Y = 29 - 5

=>2Y = 24

=>Y = 24 ÷ 2

=>Y = 12

And, X = Y + 5

=>X = 12 + 5 = 17

Therefore, 17 and 12 are the two numbers.