Two forces 2n and 4n are inclined at an angle of 120 find the magnitude and direction of their resultant
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Magnitude = 2√3n & Direction = 90° to 2n
Step-by-step explanation:
Two forces 2n and 4n are inclined at an angle of 120 deg
To Simplify let say 2n is along +ve x axis & 4n is inclined at 120 deg
i - along x axis
j - along y axis
2n = 2n i + 0 j
4n = 4n Cos120 i + 4nSin120 j
= 4n(-0.5)i + 4n(√3 / 2) j
= -2n i + 2√3n j
Resultant = 2n i + 0 j + (-2n i + 2√3n j)
= 0 i + 2√3n j
= 2√3n j
Magnitude = 2√3n
Direction = 90° to 2n
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