Question

Sum of two numbers is 40 and their difference is 4. The ratio of the numbers is

Answer 1

Answer:

Let the two numbers be x and y:

x+y=40 (1)

x-y=4 (2)

(1)+(2): 2x=44, x=22

Subsitute x=22 into (1):

y+22=40, y=18

Ratio: $\frac{y}{x} =\frac{22}{18} =\frac{11}{9}=11:9$

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Step-by-step explanation:

Answer 2

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Here is your answer.

Let the Numbers are x and y
ATQ
$x + y = 40 \\ and \\ x - y = 4$
On Adding above equation we get
$2x = 44 \\ x = 22$
Put it in above equation

$22 + y = 40 \\ y = 40 - 22 \\ y = 18$
Now The Ratio of the Number is
$\frac{22}{18} \\ = \frac{11}{9} \\ \\ or \\ \frac{18}{22} \\ = \frac{9}{11}$
Therefore the Ratio of the number can be

11 : 9. OR. 9 : 11

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