Sum of two numbers is 50 and sum of three reciprocal is 1/12 so find these two numbers
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Answer:
first number = 30, second number = 20
Step-by-step explanation:
let first number is X
second number is 50-X
1/X+1/50-X= 1/12
X+50-X/X(50-X)= 1/12
50/50X-X^2= 1/12
12*50= 50X-X^2
600= 50X-X^2
X^2-50X+600=0
X^2-30X-20X+600=0
X(X-30)-20(X-30)=0
(X-30), (X-20)
X= 30,20
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