sum of two numbers is 50 and the difference is 10 then find the numbers std 10 ncert
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let x and y be two numbers
given,
x+y=50
x-y=10
from second equation, x=y+10
substitute in first equation,
y+10+y=50
2y+10=50
2y=40
y=20
y=20 substitute in first equation
x+20=50
x=30
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