Question

sum of two numbers is 55 .If one of the number exceeds another by 7 find the number​

Answer 1

Answer:

The numbers are 24 and 31

Step-by-step explanation:

Here we have been asked to find the numbers whose sum is 55 and the other number exceeds the first number by 7.

let the first number be x

Therefore the second number would be x+7

according to the question, we know that

x+x+7 = 55

⇒ 2x +7 = 55

⇒ 2x = 55 -7

⇒ 2x = 48

⇒ x = 48 ÷ 2

⇒ x = 24

Thus the second number would be

x+7

24+7=31

Hence the two numbers are 24 and 31 respectively.

Answer 2

Answer:

Hence value of number will be 24 and 31

Step-by-step explanation:

In context to questions asked

We have to determine the value of number

As per questions

We have

Sum of two numbers is 55

As here,

One number exceed the other by 7

So let the first number be x

and second number be (x+7)

So from above

We can write it as,

$x + (x + 7) = 55 \\ = > x + x = 55 - 7 \\ = > 2x = 48 \\ = > x = \frac{48}{2} \\ = > x = 24$

Hence value of number will be 24 and 31