Question

sum of two numbers is 74. One number is 10 more than the other. what are the number​

Answer 1

Heya!❤️

Solution :

Let one number be x and other be x+10

A/Q

$x + x + 10 = 74$

$2x + 10 = 74$

$2x = 74 - 10$

$2x = 64$

$x = \frac{64}{2}$

$x = 32$

Numbers are 32 and 32+10 = 42

Verification:

$32 + 42 = 74$

Hope this helps

@adiba31☺️❤️☺️

Answer 2

Answer:

HEY GUYS. . . . . . . . . .

HERE IS YOUR ANSWER. . . . . .

Step-by-step explanation:

LET THE 1ST NO. BE X

SO, THE 2ND NO. = 10+X

ACCORDING TO THE QUESTION

X+(10+X) = 74

=> X+10+X = 74

=> 2X+10 =74

=> 2X = 74-10

=> X= 64÷2

=> X= 32

SO, THE 1ST NO. = 32

AND 2ND NO. = 10+32

= 42