Question

Sum of two numbers is 95. If one exceeds the other by 15, find the numbers​

Answer 1

$\pink{given : } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ x + y = 95 \\ \\ x = y + 15 \\ \\ \pink{to \: \: \: find : } \: \: \: x \: \: \: \: nd \: \: \: \: \: \: \: y \: \: \: \\ \\ \pink{soluton : } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ x + y = 95 \\ \\y + y + 15 = 95 \\ \\2 y = 80 \\ \\y = 40 \\ \\ x = 40 + 15 \\ \\ = 55$

Answer 2

Answer:

$\huge \mathfrak \pink{Given \implies}$

Let one number be x

Other number = x + 15

As per the condition of the question, we get

x + (x + 15) = 95

⇒ x + x + 15 = 95

⇒ 2x + 15 = 95

⇒ 2x = 95 – 15 [transposing 15 from (+) to (-)]

⇒ 2x = 80

⇒ x = 80/2 [transposing 2 from (×) to (÷)]

⇒ x = 40

Other number = 95 – 40 = 55

Thus, the required numbers are 40 and 55.

Hope it's help you....❤️