Sum of two numbers is 95. If one exceeds the other by 15, find the numbers.
Answers
Given :-
Sum of two numbers is 95.
One exceeds the other by 15.
To Find :-
What are the numbers.
Solution :-
Let,
\leadsto \bf{First\: number =\: y}⇝Firstnumber=y
\leadsto \bf{Second\: number =\: y + 15}⇝Secondnumber=y+15
Given :
\bullet∙ Sum of two numbers is 95.
According to the question,
\implies \sf y + y + 15 =\: 95⟹y+y+15=95
\implies \sf 2y + 15 =\: 95⟹2y+15=95
\implies \sf 2y =\: 95 - 15⟹2y=95−15
\implies \sf 2y =\: 80⟹2y=80
\implies \sf y =\: \dfrac{\cancel{80}}{\cancel{2}}⟹y=
2
80
\implies \sf y =\: \dfrac{40}{1}⟹y=
1
40
\implies \sf\bold{\purple{y =\: 40}}⟹y=40
Hence, the required numbers are :
➲ First Number :
\longrightarrow \sf First\: number =\: y⟶Firstnumber=y
\longrightarrow \sf\bold{\red{First\: number =\: 40}}⟶Firstnumber=40
➲ Second Number :
\longrightarrow \sf Second\: number =\: y + 15⟶Secondnumber=y+15
\longrightarrow \sf Second\: number =\: 40 + 15⟶Secondnumber=40+15
\longrightarrow \sf \bold{\red{Second\: number =\: 55}}⟶Secondnumber=55
{\small{\bold{\purple{\underline{\therefore\: The\: numbers\: are\: 40\: and\: 55\: .}}}}}
∴Thenumbersare40and55.
Explanation:
Sum of two numbers is 95. If one exceeds the other by 15, find the numbers. Let the first number be x, then another number be x + 15. And another number = 40 + 15 = 55.