Question

sum of two numbers is 95 if one exceeds The Other by 3 find the number​

Answer 1

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Required answer:

The two numbers are 46 and 49.

Given information:

Sum of two numbers is 95.

One exceeds the other by 3.

Need to find out:

The two numbers is = ?

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Let the one number = x

Then,

The other number = x + 3

According to the given question:

=> x + x + 3 = 95

=> 2x + 3 = 95

=> 2x = 95 - 3

=> 2x = 92

=> x = 46

So,

The number is 46.

Therefore,

Other number = 46 + 3 = 49

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=> 46 + 48

=> 95

i.e. the sum of two numbers is 95.

Answer 2

Answer:

Let the one number be x and the other number be y.

It is given that the sum of the numbers is 95, therefore, we have:

x+y=95....(1)

It is also given that one number exceeds the other by 3 which means:

x=y+3

⇒x−y=3....(2)

Now, we add equations 1 and 2 as follows:

x+y+x−y=95+3

⇒(x+x)+(y−y)=98

⇒2x=98

⇒x=

2

98

⇒x=49

Now, substitute the value of x in equation 2 to find the value of y as shown below:

x−y=3

⇒49−y=3

⇒y=49−3

⇒y=46

Therefore, the two numbers are x=49 and y=46 and the product of the numbers is:

x×y=49×46=2254.

Hence, the product of the numbers is 2254