Question

sum of zereos of the polynomial ax^2+bx+.c will be
(a) -b/a (b) c/a (c) a/c (d) -a/b

Answer 1

a)-b/a

solution :-

ax^2+bc+c
a(alpha)+b(beta)= -coefficient of x/coefficient of x^2

That's why sum of zeroes ax^2+bx+c is -b/a

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