Question

Suma is a twice as old as her brother in 6 years time the sum of their ages will be 39 and what are their age now

Answer 1

Answer:

Brother's present age is 9 years and Suma's present age is 18 years

Step-by-step explanation:

Let the age of brother be x

We are given that  Suma is a twice as old as her brother

So, Suma's age = 2x

After 6 years

Brother's age = x+6

Suma's age =2x+6

We are given that  in 6 years time the sum of their ages will be 39

So, $x+6+2x+6=39$

$3x+12=39$

$3x=27$

$x=9$

So, Brother's present age = 9 years

Suma's present age = 2x =2(9)=18 years

Hence  Brother's present age is 9 years and Suma's present age is 18 years

Answer 2

Concept

An equation is the expression of a variable in which different quantities are expressed.

Given

The sum of their ages will be 39.

To find

Their age now?

Explanation

let the present age of Suma be x and her brother will be y.

According to the question

x=2y

x-2y=0 ........1

x+6+y+6=39

x+y=27 .......2

take equation 1 and find the value of x

x=2y

put the value of x in 2

2y+y=27

3y=27

y=9

put the value of y in x=2y

x=2*9

x=18

Hence their age now is 18 years and 9 years.

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