Sume of natural numbers cube explantaion of formula
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Hello friend
Formula is
1^3 + 2^3 + ... +N^3 = {n(n+1)/2}^2
You can verify it by putting the value of n = 1,2,3...
N= 1
Sum = {1×(1+1)/2}^2 = 1
Hope it will help you !!
Formula is
1^3 + 2^3 + ... +N^3 = {n(n+1)/2}^2
You can verify it by putting the value of n = 1,2,3...
N= 1
Sum = {1×(1+1)/2}^2 = 1
Hope it will help you !!
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