Sumi is now 9 years older than her brother. In 10 years , Sumi will be twice as old as her brother 10 years ago. Find their present ages.
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Sumi`s brother present age=x
sumi present age=x+9
10 years ago
Sumi's brother age=x-10
sumi age=x+9-10
=x-1
ATQ
(x-1)2=x+10
2x-2=x+10
2x-x=10+2
x=12
Sumi's brother present age=12 year
sumi present age=x+9
=12+9
=21 year
sumi present age=x+9
10 years ago
Sumi's brother age=x-10
sumi age=x+9-10
=x-1
ATQ
(x-1)2=x+10
2x-2=x+10
2x-x=10+2
x=12
Sumi's brother present age=12 year
sumi present age=x+9
=12+9
=21 year
sonukumar985:
iam wrong
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