Math, asked by nayan62, 11 months ago

Sumit made reservation for an office lunch at a local restaurant for two days. on the first day employees sat in group of 9 while on the second day thay sat in group of 11 what is the smallest number of people who went for lunch.




Answers

Answered by JenettTanu
4

Answer:

9

is the answer

hope it is correct

Answered by sk940178
14

Answer:

99

Step-by-step explanation:

It is given that, on the first day of the office lunch the office employees sat in a group of 9.

So, the number of office employees must be a multiple of 9.

Again, it is given that, on the second day of the office lunch the same number of office employees sat in a group of 11.

So, the number of office employees must be a multiple of 11.

Hence, the smallest number of employees who went for lunch will be (9*11) = 99. (Answer)

Similar questions