Math, asked by Jain111, 1 year ago

Sumit wanted to pick up his bike parked at Ravi's house. He took an auto -rickshaw from his house to Ravi's house. The speed of the auto - rickshaw was 15km/h.He. He then drove back on his bike at the speed of 60 km /h.The entire trip took him four hours. how far is Sum it's house from Ravi's house?

Answers

Answered by akku42
22
s=d/t
d/15+d/60=4hr
distance=48/2=24km
Answered by yashudeshmukh6895
1

Answer:

48km

Step-by-step explanation:

given

speed = 15km/hr

2nd speed = 60km/hr

time =4hrs

we have to find distance

time = distance/speed

4 = d/15 + d/60

LCM of 15&60 is 60

4= d×4/15×4 + d/60

4= 4d/60+d/60

4= 5d/60

4×60= 5d

240= 5d

240/5 = d

48 =d

therefore total distance is 48 km

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