sumof first n terms of G.P.
if common difference is equal to 1
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sum of n terms of G. P = a(1-r^n)/(1-r)
were
a = first term
r = common ratio
here given r = 1 so
sum = a(1-1)/(1-1) = a(0/0) = undefined
actually a G. p like that can't be formed it does not exit since sum is undefined
were
a = first term
r = common ratio
here given r = 1 so
sum = a(1-1)/(1-1) = a(0/0) = undefined
actually a G. p like that can't be formed it does not exit since sum is undefined
i don't understand
foolow to krr
first tu kar
1 cannot be a common ratio for an G. P if it is a common ratio then that sequence should be an A.P
hope now you had understand
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