Question

Sumota is twice as old as ashima. If six years is subtracted from ashima's age and four years added to sumita's age, then sumita will be foir times ashmita's age. How old wjere they two years ago?​

Answer 1

Step-by-step explanation:

two years ago Samita was 4 years less than ashmina

12 years ago Ashima was born only 0 years old 4 years less than Sunita

Answer 2

Answer:

Sumita was 26 years old and Ashima 12 years old (2 years ago).

Step-by-step explanation:

Let Ashima's present age be x years

Then Sumita's age= 2x (given)

According to question,

4(x-6)=2x+4

4x-24=2x+4

4x-2x=4+24

2x=28

x=28/2

x=14

Therefore, Ashima's present age is 14 years and Sumita's present age is (2*14)=28 years.

To find-

Ashima's age 2 years ago=14-2=12 years

Sumita's age 2 years ago=28-2=26 years

That's the correct answer

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